Sketch and write the equation for each line answer key

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Kuta Software - Infinite Pre-Algebra Name Graphing Lines in Standard Form Sketch the graph of each line. 1 x y 2 x y y x 3 x y 4 x 5 x y 6 x y 0 y210R192W FKwuVtqaF dSVoAfot5whaLroes SLnLlC1. d V 4ASl4lA OrIiMgWhRt6sd rrJeps9eErUvHeKde. u L gM7addQei Twxi7t2hz XIAnwfJignhiFtkez DPBrbeL-jAxlQg0eIbJraak. V -1- Worksheet by Kuta Software LLC 8 x y 7 x y 9 y B o23041a2S hK4uSt7aK SSqolfbtgwZaRrKeN 0LSLhCR*O o VAblwlC Nr3i5ghhQtasJ fruedseehrpvsegdE*6 6 xMTaAdced...

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So matching this up to our infamous equation y equals MX plus B we see that the y-intercept is negative 2, so I'm going to start there I know for sure that's a point on my line, and then it's got a slope of 7 over 2, so that's the rise over the run so went from that point I want to rise up 1 2 3 4 5 6 7 and run over 2, and then I'm going to connect the dots and graph my line if I could keep going I would, but I'll just use those two points all right let me do it again so this guy here I can see my y-intercept is a positive 3, so that's where it intercepts the y-axis right there from that point I know my slope is negative 6 so since my slope is my rise over my run that's negative 6 over 1, so it's negative 6, so I'm going to go down 6 and then to the right 1 so down 1 2 3 4 5 6 over to the right 1, and I connect those dots there we go, and so I can tell take a step back I can tell that it has a nice and negative slope because if I were to write on my line from left to right my letters would be going down, so it's going down this way, so I graphed it right, so I decided to go down 6 and then to the right one I could have also decided to go up 6 into the left one from that point I could have gone up 1 2 3 4 5 and 6 and over to the left one, and I would have still ended up on my line, so we do it again this one throws people what's it like where's the X, but it's actually not so bad y is negative 5 so Y is certainly negative 5 down there, and it's also negative 5 at this point and at that point and at that point and at that point and at that point so if you were to label like any of these ordered pairs like this point here would be negative 3 on the X negative 5 on the Y this guy here would be seen this one here would be two on the X negative 5 on the Y this guy here would be four on the X negative 5 on why every single ordered pair has a y-coordinate of negative 5 so y equals negative 5 is a perfect equation for that one so back to something a bit more normal, so we have a y-intercept of 1 start there we have a slope of 6 over 5 so rise 6 run 5 from that point so from that y-intercept 1 2 3 4 5 6 up 1 2 3 4 5 5 over I could have also because I fell off the graph maybe isn't 6 over 5 the same thing as negative 6 divided by negative 5, but negative divided by negative would still be positive so from that point I could have gone down 1 2 3 4 5 6 and ran over 1 2 3 4 5 so down is the negative direction and to the left is the negative direction and so those two negatives made a positive and my line is you go still going with a nice and positive stuff up because remember the original was just a positive 6 over 5 what will you do it again y-intercept a 2, so we'll start there slope of 1/4 so up 1 over 1 2 3 4 if I want more points on the line I could also go down 1 and to the left 4 so down 1 1 2 3 4 so on my line and there is my pretty much excellent do it again this one here x equals 5 huh well I certainly equal 5 over here right, and it also equals 5...

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