Show Equation of a circle given the centre and the radiusCenterStandard form equation of a circle General form equation of a circle
Parametric form equation of a circle Equation of a circleAn equation of a circle is an algebraic way to define all points that lie on the circumference of the circle. That is, if the point satisfies the equation of the circle, it lies on the circle's circumference. There are different forms of the equation of a circle:
General Form Equation of a CircleThe general equation of a circle with the center at , where With general form, it is difficult to reason about the circle's properties, namely the center and the radius. But it can easily be converted into standard form, which is much easier to understand. Standard Form Equation of a CircleThe standard equation of a circle with the center at
and radius is Parametric Form Equation of a CircleThe parametric equation of a circle with the center at and radius is Polar Form Equation of a CircleThe polar form looks somewhat similar to the standard form, but it requires the center of the circle to be in polar coordinates from the origin. In this case, the polar coordinates on a point on the circumference must satisfy the following equation This calculator will find either the equation of the circle from the given parameters or the center, radius, diameter, circumference (perimeter), area, eccentricity, linear eccentricity, x-intercepts, y-intercepts, domain, and range of the entered circle. Also, it will graph the circle. Steps are available. Related calculators: Parabola Calculator, Ellipse Calculator, Hyperbola Calculator, Conic Section Calculator Your InputFind the center, radius, diameter, circumference, area, eccentricity, linear eccentricity, x-intercepts, y-intercepts, domain, and range of the circle $$$x^{2} + y^{2} = 9$$$. SolutionThe standard form of the equation of a circle is $$$\left(x - h\right)^{2} + \left(y - k\right)^{2} = r^{2}$$$, where $$$\left(h, k\right)$$$ is the center of the circle and $$$r$$$ is the radius. Our circle in this form is $$$\left(x - 0\right)^{2} + \left(y - 0\right)^{2} = 3^{2}$$$. Thus, $$$h = 0$$$, $$$k = 0$$$, $$$r = 3$$$. The standard form is $$$x^{2} + y^{2} = 9$$$. The general form can be found by moving everything to the left side and expanding (if needed): $$$x^{2} + y^{2} - 9 = 0$$$. Center: $$$\left(0, 0\right)$$$. Radius: $$$r = 3$$$. Diameter: $$$d = 2 r = 6$$$. Circumference: $$$C = 2 \pi r = 6 \pi$$$. Area: $$$A = \pi r^{2} = 9 \pi$$$. Both eccentricity and linear eccentricity of a circle equal $$$0$$$. The x-intercepts can be found by setting $$$y = 0$$$ in the equation and solving for $$$x$$$ (for steps, see intercepts calculator). x-intercepts: $$$\left(-3, 0\right)$$$, $$$\left(3, 0\right)$$$ The y-intercepts can be found by setting $$$x = 0$$$ in the equation and solving for $$$y$$$: (for steps, see intercepts calculator). y-intercepts: $$$\left(0, -3\right)$$$, $$$\left(0, 3\right)$$$ The domain is $$$\left[h - r, h + r\right] = \left[-3, 3\right]$$$. The range is $$$\left[k - r, k + r\right] = \left[-3, 3\right]$$$. AnswerStandard form: $$$x^{2} + y^{2} = 9$$$A. General form: $$$x^{2} + y^{2} - 9 = 0$$$A. Graph: see the graphing calculator. Center: $$$\left(0, 0\right)$$$A. Radius: $$$3$$$A. Diameter: $$$6$$$A. Circumference: $$$6 \pi\approx 18.849555921538759$$$A. Area: $$$9 \pi\approx 28.274333882308139$$$A. Eccentricity: $$$0$$$A. Linear eccentricity: $$$0$$$A. x-intercepts: $$$\left(-3, 0\right)$$$, $$$\left(3, 0\right)$$$A. y-intercepts: $$$\left(0, -3\right)$$$, $$$\left(0, 3\right)$$$A. Domain: $$$\left[-3, 3\right]$$$A. Range: $$$\left[-3, 3\right]$$$A. How do you find the equation of a circle with two points and tangent?The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. If a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.
How do you find the equation of a circle with only the center?Example. Find the equation of the circle with centre and radius . x 2 + y 2 + 2 g x + 2 f y + c = 0 is used to work out the centre of the circle, and the radius. ( x − a ) 2 + ( y − b ) 2 = r 2 is used to write the equation of the circle when you know the centre and the radius.
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